.5x^2+5x+3=0

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Solution for .5x^2+5x+3=0 equation: 



.5x^2+5x+3=0

a = .5; b = 5; c = +3;
Δ = b2-4ac
Δ = 52-4·.5·3
Δ = 19
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{19}}{2*.5}=\frac{-5-\sqrt{19}}{1}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{19}}{2*.5}=\frac{-5+\sqrt{19}}{1}
$

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